Question

On reversing a reaction equilibrium $(\Delta n=0)$ , the numerical value of $K_c$ and its unit both are reversed.

• A. True
• B. False

Answer 1

The correct option is A True

For a reaction $aA+bB\rightleftharpoons cC+dD$,

$K=\frac{C^c{D}^d}{A^a{B}^b}$

For, $cC+dD\rightleftharpoons aA+bB$,

$K=\frac{A^a{B}^b}{C^c{D}^d}$
Thus, $K^{\prime }=1/K$. and units are also reversed.