Question

On reversing a reaction equilibrium $(\Delta n\ne 0)$, the numerical value of $K_c$ and its units both are reversed.
If true enter 1, if false enter 0.

Answer 1

On reversing a reaction equilibrium $(\Delta n\ne 0)$, the numerical value of $K_c$ and its units both are reversed.

For example, consider a reaction $A\rightleftharpoons 2B$ with $\left[A\right]=xM,\left[B\right]=yM$. The equilibrium constant expression is

$K_c=\frac{[B{]}^2}{\left[A\right]}=\frac{(yM{)}^2}{xM}=\frac{y^2}{x}M.$

Now, the above reaction is reversed.
$2B\rightleftharpoons A$

The value of the equilibrium constant is $K_c^{\prime }=\frac{\left[A\right]}{[B{]}^2}=\frac{xM}{(yM{)}^2}=\frac{x}{y^2}{M}^{-1}$.