On seeing a board of speed limit, you apply brakes that brings the car from speed of 108km/h to a speed of 72km/h, covering a distance of 100m at a constant deceleration. How much time is required for the given decrease in speed?
A
3sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B4sec Initial speed, u=108km/h=30m/s Final speed, v=72km/h=20m/s Using third equation of motion, v2=u2+2as a=(v2−u2)2s=202−3022×100 a=−2.5m/s2 Using first equation of motion, v=u+at t=v−ua t=20−30−2.5=4sec