Question

On selfing a plant of $F_1$ generation with genotype "AABbCC", the genotypic ratio in $F_2$-generation will be

• A. $1:2:1$
• B. $1:1$
• C. $9:3:3:1$
• D. $27:9:9:9:3:3:3:1$

Answer 1

The correct option is A $1:2:1$

The possible gametes from the given genotype AABbCC are ABC and AbC.

The various possibilities of their their selfing would be :

1. ABC × ABC = AABBCC

2. ABC × AbC = AABbCC

3. AbC × ABC = AABbCC

4. AbC × AbC = AAbbCC

It is evident from the above crosses that the genotypic ratio of F2 generation will be 1:2:1.

So, the correct option is '1:2:1'.