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Byju's Answer
Standard X
Mathematics
Solving a Quadratic Equation by Factorization Method
On selling 1 ...
Question
On selling 1 kg sugar for Rs 16.50 the profit was 10%. What was the cost price per kilogram?
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Solution
Let the cost price of 1 kg sugar = C.P = Rs x
Selling price of 1 kg sugar = S.P = Rs 16.50
Profit % = 10%
Profit = S.P - C.P
= Rs (16.50 – x)
Profit % =
Profit
C
.
P
×
100
⇒
10
=
16
.
50
-
x
x
×
100
⇒
10
x
=
16
.
50
-
x
×
100
⇒
10
x
=
1650
-
100
x
⇒
10
x
+
100
x
=
1650
⇒
110
x
=
1650
⇒
x
=
1650
110
⇒
x
=
15
∴ Cost price of 1 kg sugar is Rs 15.
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