On selling a fan for Rs 2585 a man gains 110 of its cost price- Find the cost price of tha fan-

Let the cost price of the fan be Rs. x. Gain = nbsp;Rs. #160;x10 SP of the fan = ( #160;x #160;+ #160;x10)= #160;Rs. #160;1110x nbsp; nbsp; ...

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Standard VII

Mathematics

Profit % Loss %

On selling a ...

Question

On selling a fan for Rs 2585 a man gains $\frac{1}{10}$ of its cost price. Find the cost price of tha fan.

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Solution

Let the cost price of the fan be Rs. x.
Gain = $Rs . \frac{x}{10}$
SP of the fan = $(x + \frac{x}{10}) = Rs . \frac{11}{10} x$
SP of the fan = $Rs . 2585$
∴ $\frac{11}{10} x = 2585$
⇒ $11 x = 25850$
⇒ $x = \frac{25850}{11} = 2350$

So, CP of the fan is Rs. 2350.

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On selling a fan for Rs 2585 a man gains 110 of its cost price. Find the cost price of tha fan.

Let the cost price of the fan be Rs. x. Gain = Rs. x10 SP of the fan = ( x + x10)= Rs. 1110x SP of the fan = Rs. 2585 ∴ 1110x = 2585 ⇒ 11x = 25850 ⇒ x = 2585011 = 2350 So, CP of the fan is Rs. 2350.

On selling a fan for Rs 2585 a man gains $\frac{1}{10}$ of its cost price. Find the cost price of tha fan.

Let the cost price of the fan be Rs. x.
Gain = $Rs . \frac{x}{10}$
SP of the fan = $(x + \frac{x}{10}) = Rs . \frac{11}{10} x$
SP of the fan = $Rs . 2585$
∴ $\frac{11}{10} x = 2585$
⇒ $11 x = 25850$
⇒ $x = \frac{25850}{11} = 2350$

So, CP of the fan is Rs. 2350.