On selling a pen for ₹100, a shopkeeper gains ₹15. The cost price of the pen is

(a) ₹115
(b) ₹85
(c) ₹70
(d) ₹130

Open in App

Solution

Let the CP be x.

SP = ₹100
Profit = ₹15

Therfore, SP is more than CP.

Now,
CP = SP − Profit
= ₹100 − ₹15
= ₹85

Thus, CP = ₹85

Hence, the correct option is (b).

Suggest Corrections

Similar questions

In the given figure $∠$ AOC= $130^{\circ}$ , The value of $∠$ ABC (in degrees) is _______.

A parallelogram-shaped mat has a height of 4 cm and a base of 3 cm. How much would it cost to cover a parallelogram-shaped hall with an area of 180 sq.cm with mats, if 1 mat costs ₹.7?

_{6}^{11} C \to_{5}^{11} B

decay produces -

Q. Mark (✓) against the correct answer
1.04 = ?

(a)

1 \frac{1}{5}

(b)

1 \frac{2}{5}

(c)

1 \frac{1}{25}

(d) none of these

(1 + x)^{15} = a_{0} + a_{1} x + \dots + a_{15} x^{15} \Rightarrow \sum_{r = 1}^{15} r \frac{a_{r}}{a_{r - 1}}

Join BYJU'S Learning Program

On selling a pen for ₹100, a shopkeeper gains ₹15. The cost price of the pen is (a) ₹115 (b) ₹85 (c) ₹70 (d) ₹130

Let the CP be x. SP = ₹100 Profit = ₹15 Therfore, SP is more than CP. Now, CP = SP − Profit = ₹100 − ₹15 = ₹85 Thus, CP = ₹85 Hence, the correct option is (b).

On selling a pen for ₹100, a shopkeeper gains ₹15. The cost price of the pen is

(a) ₹115
(b) ₹85
(c) ₹70
(d) ₹130

Let the CP be x.

SP = ₹100
Profit = ₹15

Therfore, SP is more than CP.

Now,
CP = SP − Profit
= ₹100 − ₹15
= ₹85

Thus, CP = ₹85

Hence, the correct option is (b).