Question

On simplification of $2\frac{1}{2}+3\frac{1}{6}-4\frac{1}{3}$, we get

• A. $\frac{1}{48}$
• B. $\frac{4}{3}$
• C. $\frac{11}{12}$
• D. $\frac{1}{8}$

Answer 1

The correct option is B

$\frac{4}{3}$

$2\frac{1}{2}+3\frac{1}{6}-4\frac{1}{3}$

=$\frac{2\times 2+1}{2}$ + $\frac{3\times 6+1}{6}$ - $\frac{4\times 3+1}{3}$

=$\frac{4+1}{2}$ + $\frac{18+1}{6}$ - $\frac{12+1}{3}$

=$\frac{5}{2}+\frac{19}{6}-\frac{13}{3}$
Taking LCM of denominators,

LCM of 2, 3 and 6 is 6

=$\frac{5\times 3+19\times 1-13\times 2}{6}$

=$\frac{15+19-26}{6}$=$\frac{8}{6}$=$\frac{4}{3}$