On simplifying 4-13-8-11-2-13-15-11- we get

The correct option is C 2√(13) 7√(11) 4√(13) 2√(13)+8√(11) 15√(11) =2√(13) 7√(11) So, option C is correct. ...

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Standard XII

Mathematics

Law of Reciprocal

On simplifyin...

Question

On simplifying $4 \sqrt{13} + 8 \sqrt{11} - 2 \sqrt{13} - 15 \sqrt{11}$ , we get

2 \sqrt{13} - 4 \sqrt{11}

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2 \sqrt{13} - 5 \sqrt{11}

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2 \sqrt{13} - 7 \sqrt{11}

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None of the above

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Solution

The correct option is C $2 \sqrt{13} - 7 \sqrt{11}$
$4 \sqrt{13} - 2 \sqrt{13} + 8 \sqrt{11} - 15 \sqrt{11}$

$= 2 \sqrt{13} - 7 \sqrt{11}$
So, option C is correct.

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Similar questions

Question 81 (i)

Simplify: $\frac{13}{11} \times \frac{- 14}{5} + \frac{13}{11} \times \frac{- 7}{5} + \frac{- 13}{11} \times \frac{34}{5}$

\frac{- 7}{5} + (\frac{2}{- 11} + \frac{- 13}{25}) = (\frac{- 7}{5} + \frac{2}{- 11}) + \frac{- 13}{25}

This property is

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

Q. If

A = {2, 3, 5, 7, 11, 13}

B = {5, 7, 9, 11, 15}

are the subsets of

U = {2, 3, 5, 7, 9, 11, 13, 15}

, verify De Morgan's laws.

2, 3, 13, 5, 7, 74, 11, 13, ?

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On simplifying 4√13+8√11−2√13−15√11, we get

The correct option is C 2√13−7√114√13−2√13+8√11−15√11=2√13−7√11So, option C is correct.

On simplifying $4 \sqrt{13} + 8 \sqrt{11} - 2 \sqrt{13} - 15 \sqrt{11}$ , we get

The correct option is C $2 \sqrt{13} - 7 \sqrt{11}$
$4 \sqrt{13} - 2 \sqrt{13} + 8 \sqrt{11} - 15 \sqrt{11}$

$= 2 \sqrt{13} - 7 \sqrt{11}$
So, option C is correct.