1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Mathematics
Solving Linear Equations Using Transpose of Terms
On simplifyin...
Question
On simplifying:
5
t
−
3
=
3
t
−
5
It gives:
t
=
2
If this is true enter 1, if false enter 0.
Open in App
Solution
Given,
5
t
−
3
=
3
t
−
5
⇒
5
t
−
3
t
=
−
5
+
3
[Transposing 3t to LHS and -3 to RHS]
⇒
2
t
=
−
2
⇒
2
t
2
=
−
2
2
[Dividing both sides by
2]
⇒
t
=
−
1
Check:
L
H
S
=
5
t
−
3
=
5
(
−
1
)
−
3
=
−
5
−
3
=
−
8
R
H
S
=
3
t
−
5
=
3
(
−
1
)
−
5
=
−
3
−
5
=
−
8
Clearly,
L
H
S
=
R
H
S
Hence checked!!
So the answer is false.
Suggest Corrections
0
Similar questions
Q.
Simplify the following:
(
√
3
−
√
2
)
2
is equal to
5
−
2
√
6
.
If true then enter
1
and if false then enter
0
.
Q.
2
x
−
1
=
14
−
x
x
=
5
If this is true enter 1, if false enter 0.
Q.
Simplify the ratios.
16
1
2
:
6
3
2
is 5:2
If true then enter
1
and if false then enter
0
Q.
Simplify:
a
5
÷
a
3
+
3
a
×
2
a
, then the answer is
7
a
2
If true then enter
1
and if false then enter
0
Q.
Simplify:
(
x
5
÷
x
2
)
×
y
2
×
y
3
, then answer is
x
3
y
5
If true then enter
1
and if false then enter
0
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Solving Linear Equations Using Transpose of Terms
MATHEMATICS
Watch in App
Explore more
Solving Linear Equations Using Transpose of Terms
Standard VIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app