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Question

On simplifying 1tanA+cotA, we get


A

sinA+cosA

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B

sinAcosA

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C

1sinAcosA

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D

tanAcotA

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Solution

The correct option is B

sinAcosA


1tanA+cotA

= 1sinAcosA+cosAsinA

= 1sin2A+cos2AsinAcosA

= 11sinAcosA

= sinAcosA


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