On simplifying- -sin 2 A -1- we will getA- AB- cos AC- sin AD- cosec A

The correct option is C sin AFrom Trigonometric identity, sin^2A + cos^2A = 1 nbsp; ⇒ sin^2A 1 = cos^2A ∴ nbsp; √(sin^2A 1)/cotA = nbsp;√(cos^2A)/cot ...

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Standard X

Mathematics

Trigonometric Identity- 1

On simplifyin...

Question

On simplifying, $\frac{\sqrt{s i n^{2} A - 1}}{c o t A}$ , we will get

cot A

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cos A

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sin A

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cosec A

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Solution

The correct option is C sin A
From Trigonometric identity,
$s i n^{2} A + c o s^{2} A = 1$
$\Rightarrow$ $s i n^{2} A - 1 = c o s^{2} A$
$∴$ $\frac{\sqrt{s i n^{2} A - 1}}{c o t A}$

= $\frac{\sqrt{c o s^{2} A}}{c o t A}$

= $\frac{c o s A}{\frac{c o s A}{s i n A}}$

= $s i n A$

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On simplifying, √sin2A−1cotA , we will get

The correct option is C sin AFrom Trigonometric identity, sin2A+cos2A=1 ⇒ sin2A−1=cos2A ∴ √sin2A−1cotA = √cos2AcotA = cosAcosAsinA = sinA

On simplifying, $\frac{\sqrt{s i n^{2} A - 1}}{c o t A}$ , we will get

The correct option is C sin A
From Trigonometric identity,
$s i n^{2} A + c o s^{2} A = 1$
$\Rightarrow$ $s i n^{2} A - 1 = c o s^{2} A$
$∴$ $\frac{\sqrt{s i n^{2} A - 1}}{c o t A}$

= $\frac{\sqrt{c o s^{2} A}}{c o t A}$

= $\frac{c o s A}{\frac{c o s A}{s i n A}}$

= $s i n A$