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Question

On solving 32xdxx2+1 we get 12logA+C as an answer. What is A in the given answer?

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Solution


I=32(xdxx2+1)letx2+1=t2xdx=dtifx=2t=5ifx=3t=10I=105(1t)dt=(12)[log|t|]105=(12)(log10log5)=(12)log2+C


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