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Standard VI

Mathematics

Solving Equations x+a = b and x-a = b by Rearranging Terms

On solving gi...

Question

On solving given equations, the value of x is , x2 – (7 – i) x + (18 – i) = 0

4+3i, 3+2i

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4-3i, 3-2i

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4-3i, 3+2i

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4+3i, 3-2i

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Solution

The correct option is C
4-3i, 3+2i

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Similar questions

Q. Solve

x^{2} - (7 - i) x + (18 - i) = 0

Solve the following quadratic equations :

(i) $x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2} i = 0$

(ii) $x^{2} - (5 - i) x + (18 + i) = 0$

(iii) $(2 + i) x^{2} - (5 - i) x + 2 (1 - i) = 0$

(iv) $x^{2} - (2 + i) x - (1 - 7 i) = 0$

(v) $i x^{2} - 4 x - 4 i = 0$

(vi) $x^{2} + 4 i x - 4 = 0$

(vii) $2 x^{2} + \sqrt{15} i x - i = 0$

(viii) $x^{2} - x + (1 + i) = 0$

(ix) $i x^{2} - x + 12 i = 0$

(x) $x^{2} - (3 \sqrt{2} - 2 i) x - \sqrt{2} i = 0$

(xi) $x^{2} - (\sqrt{2} + i) x + \sqrt{2} i = 0$

(xii) $2 x^{2} - (3 + 7 i) x + (9 i - 3) = 0$

Q. Solve the following quadratic equations:
(i)

x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2 i} = 0

(ii)

x^{2} - (5 - i) x + (18 + i) = 0

(iii)

(2 + i) x^{2} - (5 - i) x + 2 (1 - i) = 0

(iv)

x^{2} - (2 + i) x - (1 - 7 i) = 0

(v)

i x^{2} - 4 x - 4 i = 0

(vi)

x^{2} + 4 i x - 4 = 0

(vii)

2 x^{2} + \sqrt{15} i x - i = 0

(viii)

x^{2} - x + (1 + i) = 0

(ix)

i x^{2} - x + 12 i = 0

(x)

x^{2} - (3 \sqrt{2} - 2 i) x - \sqrt{2} i = 0

(xi)

x^{2} - (\sqrt{2} + i) x + \sqrt{2} i = 0

(xii)

2 x^{2} - (3 + 7 i) x + (9 i - 3) = 0

Solve the quadratic equation x² – ix + 6 = 0.

Solve the following equations and verify your answer :

Find a positive value of x for which the given equation is satisfied :

(i) $\frac{x^{2} - 9}{5 + x^{2}} = - \frac{5}{9}$

(ii) $\frac{y^{2} + 4}{3 y^{2} + 7} = \frac{1}{2}$

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On solving given equations, the value of x is , x2 – (7 – i) x + (18 – i) = 0

The correct option is C 4-3i, 3+2i

The correct option is C
4-3i, 3+2i