On stretching a wire of Young's modulus $Y$ having original length $L$ by an amount $l$ using a force $F$ , the elastic energy stored per unit volume is

$\frac{F l}{2 A L}$

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$\frac{F A}{2 L}$

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$\frac{F L}{2 A}$

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$\frac{F L}{2}$

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Solution

The correct option is A
$\frac{F l}{2 A L}$

Energy stored per unit volume = $\frac{1}{2} \times s t r e s s \times s t r a i n$

$= \frac{1}{2} (\frac{F}{A}) (\frac{l}{L}) = \frac{F l}{2 A L}$

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On stretching a wire of Young's modulus Y having original length L by an amount l using a force F, the elastic energy stored per unit volume is

The correct option is A Fl2AL Energy stored per unit volume = 12×stress×strain =12(FA)(lL)=Fl2AL

On stretching a wire of Young's modulus $Y$ having original length $L$ by an amount $l$ using a force $F$ , the elastic energy stored per unit volume is

The correct option is A
$\frac{F l}{2 A L}$

Energy stored per unit volume = $\frac{1}{2} \times s t r e s s \times s t r a i n$

$= \frac{1}{2} (\frac{F}{A}) (\frac{l}{L}) = \frac{F l}{2 A L}$