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Common Ion Effect

On the additi...

Question

On the addition of a solution containing $C r O_{4}^{2 -}$ ions to the solution of ${B a}^{2 +}, {S r}^{2 +}, {C a}^{2 +}$ ions, the precipitate obtained first will be of:

C a C r O_{4}

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S r C r O_{4}

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B a C r O_{4}

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A mixture of all the three

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Solution

The correct option is C $B a C r O_{4}$
As we move down the 2nd group of periodic table solubility decreases.

As the $B a^{2 +}$ is less soluble in water.

So, $B a^{2 +}$ will precipitate out first.

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Similar questions

C r O_{4}^{2 -}

B a^{2 +}, S r^{2 +}

C a^{2 +}

B a^{2 +}

S r^{2 +}

C a^{2 +}

0.05 m o l . {l i t r e}^{- 1}

{B a}^{2 +}

0.002 m o l . l i t r e

{A g}^{+}

C r O_{4}^{2 -}

K_{s p} ({A g}_{2} C r O_{4}) = 3 \times 10^{12}; K_{s p} (B a C r O_{4}) = 1 \times 10^{- 10}

B a^{2 +}

B a C r O_{4}

S r C r O_{4}

C a C r O_{4}

C a^{2 +} (a q)

H C O_{3}^{-} (a q)

C a^{2 +}

H C O_{3}

C O_{3}^{2 -}

C a^{2 +}

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