On the basis of details given about two measuring instruments- select the correct statement-i Vernier callipers having main scale division -0-05 cm and vernier scale division -2-45-50 cmii Screw gauge having pitch 0-5 mm and its circular scale has 50 divisionsA- Both the instruments have same least count but screw gauge can be more precise-B- Both the instrument have same least countC- Least count of screw gauge is lesser than that of verniercallipers-D- Both the instruments have different least count and screw gauge is more precise-

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On the basis ...

Question

On the basis of details given about two measuring instruments, select the correct statement:

(i) Vernier callipers having main scale division = 0.05 cm and vernier scale division = $\frac{2.45}{50}$ cm

(ii) Screw gauge having pitch 0.5 mm and its circular scale has 50 divisions

Both the instrument have same least count

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Least count of screw gauge is lesser than that of verniercallipers.

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Both the instruments have same least count but screw gauge can be more precise.

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Both the instruments have different least count and screw gauge is more precise.

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Solution

The correct option is C
Both the instruments have same least count but screw gauge can be more precise.

L.C of vernier =M.S.D – V.S.D = [5 - 49] $10^{- 4}$ m = 0.01 mm

L.C. of screw gauge =0.01mm

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On the basis of details given about two measuring instruments, select the correct statement: (i) Vernier callipers having main scale division = 0.05 cm and vernier scale division = 2.4550cm (ii) Screw gauge having pitch 0.5 mm and its circular scale has 50 divisions

The correct option is C Both the instruments have same least count but screw gauge can be more precise. L.C of vernier =M.S.D – V.S.D = [5 - 49]10−4 m = 0.01 mm L.C. of screw gauge =0.01mm

On the basis of details given about two measuring instruments, select the correct statement:

(i) Vernier callipers having main scale division = 0.05 cm and vernier scale division = $\frac{2.45}{50}$ cm

(ii) Screw gauge having pitch 0.5 mm and its circular scale has 50 divisions

The correct option is C
Both the instruments have same least count but screw gauge can be more precise.

L.C of vernier =M.S.D – V.S.D = [5 - 49] $10^{- 4}$ m = 0.01 mm

L.C. of screw gauge =0.01mm