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Question

On the basis of information available from the reaction

43Al+O223Al2O3,ΔG=827 kJ.mol1

The minimum emf required to carry out the electrolysis of Al2O3 is:

[F=96500 C mol1]


A
2.14 V
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B
4.28 V
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C
6.42 V
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D
8.56 V
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Solution

The correct option is A 2.14 V
One mole of oxygen requires 4 moles of electrons.

The relationship between emf of cell and free energy change is ΔG=nFEcell.

Substitute values in the above expression.

827000 Jmol=4× 96500×Ecell

Ecell=2.14 V.

Hence, the correct option is A

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