On the basis of intermolecular forces predict the correct order of decreasing boiling points of the compounds :

C H_{3} O H > H_{2} > C H_{4}

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C H_{3} O H > C H_{4} > H_{2}

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C H_{4} > C H_{3} O H > H_{2}

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H_{2} > C H_{4} > C H_{3} O H

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Solution

The correct option is B $C H_{3} O H > C H_{4} > H_{2}$
Option (B) is correct.
Alcohol involves $H$ -bonding, thus have highest boiling point; also molar mass of $C H_{4}$ > molar mass of $H_{2}$ . Greater is molar mass of covalent compound higher is its boiling point.SO boiling point of methane is higher than hydrogen.

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Question 1
Calculate the molecular masses of $H_{2}, O_{2}, C l_{2}, C O_{2}, C H_{4}, C_{2} H_{6}, C_{2} H_{4}, N H_{3}, C H_{3} O H$ .

H_{2}, O_{2}, C l_{2}, C O_{2}, C H_{4}, C_{2} H_{6}, C_{2} H_{4}, N H_{3}, C H_{3} O H

H F, C H_{3} O H, N_{2} H_{4}, C H_{4}

C H_{4} + \frac{1}{2} O_{2} \to C H_{3} O H

C H_{4}

C H_{3} O H

C H_{4} + \frac{1}{2} O_{2} ⟶ C H_{3} O H

C H_{4}

C H_{3} O H

x

y

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