On the basis of position in the electrochemical series, the metal which does not displace $H_{2}$ from water and acid is :

H g

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A l

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P b

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B a

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Solution

The correct option is A $H g$
Because Reduction potential $E M^{n +} / M$ in case of $H g$ is $+ v e$ while in case of other it is $- v e$ . So reduction of $H^{+} + e^{-} \to \frac{1}{2} H_{2}$ will occur in all three other cases. So they will displace $H_{2}$ from water and acid.

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On the basis of position in the electrochemical series, the metal which does not displace H2 from water and acid is :

The correct option is A HgBecause Reduction potential EMn+/M in case of Hg is +ve while in case of other it is −ve. So reduction of H++e−→12H2 will occur in all three other cases. So they will displace H2 from water and acid.

On the basis of position in the electrochemical series, the metal which does not displace $H_{2}$ from water and acid is :

The correct option is A $H g$
Because Reduction potential $E M^{n +} / M$ in case of $H g$ is $+ v e$ while in case of other it is $- v e$ . So reduction of $H^{+} + e^{-} \to \frac{1}{2} H_{2}$ will occur in all three other cases. So they will displace $H_{2}$ from water and acid.