On the basis of the following E values, the strongest oxidizing agent is:
[Fe(CN)6]4−→[Fe(CN)6]3−+e−1,E0=−0.35V
Fe2+→Fe3++e−1,E0=−0.77V
A
Fe3+
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B
[Fe(CN)6]3−
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C
[Fe(CN)6]4−
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D
Fe2+
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Solution
The correct option is B[Fe(CN)6]3− The substance with higher oxidation potential is the stronger oxidizing agent as higher the oxidation potential lower would be the Gibbs' free energy.
Thus here [Fe(CN)6]3− will be the strongest oxidizing agent as it has higher oxidation potential.