Question

On the basis of their positions in the periodic table, select the atom with the larger atomic radius in each of the following pairs:

(a) $Na,Cs$
(b) $Be,Ba$
(c)$N,Sb$
(D)$F,Br$
(e) $Ne,Xe$

• A. $\left(a\right)Cs\left(b\right)Ba\left(c\right)Sb\left(d\right)Br\left(e\right)Xe$
• B. $\left(a\right)Cs\left(b\right)Be\left(c\right)Sb\left(d\right)Br\left(e\right)Xe$
• C. $\left(a\right)Cs\left(b\right)Ba\left(c\right)Sb\left(d\right)BF\left(e\right)Xe$
• D. None of these

Answer 1

The correct option is A $\left(a\right)Cs\left(b\right)Ba\left(c\right)Sb\left(d\right)Br\left(e\right)Xe$

In a group, the atomic radius increases from top to bottom as the number of shell increases.

(a) $Cs$ has the larger atomic radius as it is lower in a group.

(b) $Ba$ has the larger atomic radius as it is lower in a group.

(c) $Sb$ has the larger atomic radius as it is lower in a group.

(d) $Br$ has the larger atomic radius as it is lower in a group.

(e) $Xe$ has the larger atomic radius as it is lower in a group.