2
Question
On the Celsius scale the absolute zero i.e. 0∘K is equal to_____.
On the Celsius scale the absolute zero i.e. 0∘K is equal to_____.
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Solution
The correct option is D −273.15∘C
We know that T (K) = 273.15 + t∘ C ⇒0 = 273.15 + t∘C⇒t = −273.15∘C
−273.15∘C
We know that T (K) = 273.15 + t∘ C ⇒0 = 273.15 + t∘C⇒t = −273.15∘C
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