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Question
On the Celsius scale the absolute zero of temperature is at___ Degree Celsius.
On the Celsius scale the absolute zero of temperature is at
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Solution
T = 273.15 + t∘ C ⇒0 = 273.15 + t∘C⇒t = −273.15∘ C
T = 273.15 + t∘ C ⇒0 = 273.15 + t∘C⇒t = −273.15∘ C
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