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Celsius Scale

On the Celsiu...

Question

On the Celsius scale the absolute zero of temperature is at

A

0°C

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B

- 32°C

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C

100°C

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D

- 273.15°C

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Solution

The correct option is D
- 273.15°C

T = 273.15 + $t^{\circ}$ C $\Rightarrow 0 = 273.15 + t^{\circ} C \Rightarrow t = - {273.15}^{\circ} C$

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Q. Answer the following:

(a) The triple-point of water is a standard fixed point in modern thermometry. Why? What is wrong in taking the melting point of ice and the boiling point of water as standard fixed points (as was originally done in the Celsius scale )?

(b) There were two fixed points in the original Celsius scale as mentioned above which were assigned the number

0^{o} C

100^{o} C

respectively. On the absolute scale one of the fixed points is the triple-point of water, which on the kelvin absolute scale is assigned the number 273.16 K. What is the other fixed point on this (kelvin) scale?

(c) The absolute temperature (Kelvin scale ) T is relate to the temperature

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t_{c} = T - 273.15

. Why do we have 273.15 in this relation and not 273.16?

(d) What is the temperature of the triple-point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ?

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