On the interval [0,1] the function x125(1−x)75 takes the maximum value at the points
A
38
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
58
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D58 Let f(x)=x125(1−x)75 f′(x)=125x124(1−x)75−75x125(1−x)74=x124(1−x)74(125(x−1)−75x) For maximum value of f(x) f′(x)=0=x124(1−x)74(125(x−1)−75x)⇒x=58atx=(0,1)f′′(x) will vanishes.