Question

On the line $y=2x-1$, what is the approximate distance between the points where $x=1$ and $x=2$?

• A. 2.24
• B. 2.27
• C. 2.31
• D. 2.42
• E. 2.45

Answer 1

The correct option is A 2.24

The distance between points $(x_1,y_1)$ and $(x_2,y_2)$ is given by $\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

For the line $y=2x-1$ , At $x=1$ we get $y=1$ and at $x=2$ we get $y=3$
So the points are $(1,1),(2,3)$
The distance between those points is $\sqrt{1+4}=\sqrt{5}=2.24$