Question

On the same graph paper, draw the straight lines represented by equations: $x=5,x+5=0,y+3=0$ and $y=3$
Also, find the area and perimeter of the rectangle formed by the intersection of these lines.

• A. Area $=60$ sq.units and perimeter $=32$ units
• B. Area $=50$ sq.units and perimeter $=16$ units
• C. Area $=80$ sq.units and perimeter $=16$ units
• D. Area $=90$ sq.units and perimeter $=32$ units

Answer 1

The correct option is A Area $=60$ sq.units and perimeter $=32$ units

Plotting the equation in the graph.
Now,
Area of rectangle=$length\times breadth$
=$10\times 6$ sq units
=$60$sq units
Perimeter of rectangle=$2\left(b\right)+2\left(h\right)$
=$2\left(6\right)+2\left(10\right)$
=$12+20$
=$32units$