On the same set of axes are drawn the graph of y=ax2+bx+c and the graph of the equation obtained by replacing x by −x in the given equation. If b≠0 and c≠0 these two graphs intersect:
A
in two points, one on the x-axis and one on the y -axis
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B
in one point located on neither axis
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C
only at the origin
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D
in one point on the x-axis
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E
in one point on the y-axis
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Solution
The correct option is E in one point on the y-axis For x≠0,ax2+bx+c≠ax2−bx+c; for x=0, ax2+bx+c=ax2−bx+c ∴ There is one intersection point (0, c); ∴ (e) is the correct choice.