The correct option is B symmetric only
G.C.D. of a and a is 'a'.
If a≠2, then G.C.D.≠2.
∴R is not reflexive.
Let a R b
⇒G.C.D. of a,b=2
i.e., (a,b)=2
⇒(b,a)=2
⇒G.C.D. of b,a=2
∴R is symmetric.
Again, let a R b and b R c
Let a=4,b=2,c=8
G.C.D. of a,b=2
G.C.D. of b,c=2
But G.C.D. of a,c=4
∴R is not transitive.