The correct option is D equivalence relation
If a is an integer, then a+2a=3a; which is divisible by 3.
⇒a R a ∀ a∈Z
∴R is reflexive.
Let a R b where a,b∈Z
⇒a+2b=3k, where k∈Z
Now,
b+2a=(3a+3b)−(a+2b)
=(3a+3b)−3k
=3(a+b−k)
⇒b+2a=3m, where m∈Z
So, a R b⇒b R a
∴R is symmetric.
Again, let a R b and b R c where a,b,c∈Z
⇒a+2b=3j and b+2c=3k
Now,
a+2b=3j
a+2(3k−2c)=3j
a+2c=3j−6k+6c
a+2c=3(j−2k+2c)
a+2c=3m, where m∈Z as j,k,c∈Z
So, a R b, b R c⇒a R c
∴R is transitive.
Hence, R is an equivalence relation.