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Question

On the set R of all real numbers, a relation R is defined by R=(a,b):1+ab>0.Then R is


A

Reflexive and symmetric only

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B

Reflexive and Transitive only

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C

Symmetric and Transitive only

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D

An equivalence relation

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Solution

The correct option is A

Reflexive and symmetric only


Explanation for correct answer:

The correct option is A: Reflexive and symmetric only

Relations on R

For reflexive:- (a,a)R1+a×a=1+a2>0 real numbers a

R is reflexive.

For symmetric:(a,b)R1+ab>01+ba>0(b,a)R

R is symmetric.

For transitivity: since 2,12R and 12,-1R but 2,-1Ras 1+2×-1=-1which is not greater than 0

Ris not transitive.

Therefore the option (A) is correct


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