Question

On the surface of the moon, a clock will

• A. run slowly
• B. run faster
• C. remain stationary
• D. depends on the clock

Answer 1

The correct option is A run slowly

Time period of pendulum $=T=2\pi \sqrt{\frac{l}{g}}$

Now, for a given length of pendulum(l) , time period will be inversely proportional to the square root of acceleration due to gravity (g)

This means that the smaller the value of $g$ greater will be the $T$

Now we know that the value of g at the surface of moon is less than that on the surface of earth

So $T$ will be greater at the surface of the moon than on the surface of earth and the clock will run slowly.

Hence correct answer is option $A$