Question

On the xy-plane, what is the area of a circle with this equation: $(x+3{)}^2+(y+4{)}^2=49$?

• A. $5\pi$
• B. $7\pi$
• C. $25\pi$
• D. $49\pi$
• E. $125\pi$

Answer 1

The correct option is D $49\pi$

We know that the standard form of the equation of a circle with centre at $(a,b)$ and radius $r$ is $(x-a{)}^2+(x-b{)}^2=r^2$
Hence, the given circle has $r^2=49$
Area of the circle $=\pi r^2=49\pi$