On three different days a man has to drive to a railway station, and he can choose from $5$ conveyances; in how many ways can he make the three journeys?

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Solution

The man has the choice of using any of the $5$ conveyances on all $3$ days
Day 1 Day 2 Day 3
5 5 5
Therefore, number of ways he can make the $3$ journeys $= 5 \times 5 \times 5 = 125$ .

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On three different days a man has to drive to a railway station, and he can choose from 5 conveyances; in how many ways can he make the three journeys?

The man has the choice of using any of the 5 conveyances on all 3 days Day 1 Day 2 Day 3 5 55Therefore, number of ways he can make the 3 journeys =5×5×5=125.

On three different days a man has to drive to a railway station, and he can choose from $5$ conveyances; in how many ways can he make the three journeys?

The man has the choice of using any of the $5$ conveyances on all $3$ days
Day 1 Day 2 Day 3
5 5 5
Therefore, number of ways he can make the $3$ journeys $= 5 \times 5 \times 5 = 125$ .