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Question

On tossing three coins simultaneously, find the probability of getting at least one head and tail.


  1. 1/4

  2. 1/2

  3. 3/4

  4. 2/3


Solution

The correct option is C

3/4


Given, a coin is tossed 3 times.

Total possible outcomes = {HHH, HHT, HTT, HTH, THH, TTH, THT, TTT}   (where H = Heads, T= Tails)

                                       = 8

Number of favourable outcomes (getting at least one head and tail) = {HHT, HTT, HTH, THH, TTH, THT}

                                                                                                            = 6

Out of 8 possible outcomes, there are 6 favourable outcomes.

We have,

Probability of an event, P(E) = number of favourable outcomestotal number of outcomes

P (getting at least one head and tail)  = 68

                                                                        =  34

Therefore, the probability of getting at least one head and a tail is 34.

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