  Question

# On tossing three coins simultaneously, find the probability of getting at least one head and tail. 1/4 1/2 3/4 2/3

Solution

## The correct option is C 3/4 Given, a coin is tossed 3 times. Total possible outcomes = {HHH, HHT, HTT, HTH, THH, TTH, THT, TTT}   (where H = Heads, T= Tails)                                        = 8 Number of favourable outcomes (getting at least one head and tail) = {HHT, HTT, HTH, THH, TTH, THT}                                                                                                             = 6 Out of 8 possible outcomes, there are 6 favourable outcomes. We have, Probability of an event, P(E) = number of favourable outcomestotal number of outcomes ⇒ P (getting at least one head and tail)  = 68                                                                         =  34 Therefore, the probability of getting at least one head and a tail is 34.  Suggest corrections  Similar questions
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