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Question

On treating ethanal with dil.NAOH,What is the product?

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Solution

Acetaldehyde undergoes aldol condensation in presence of dil NaOH or K2CO3 to form beta hydroxy butyraldehyde or aldol.

CH3CHO + HCH2CHO—–> CH3CH(OH)CH2CHO [Aldol]

On heating aldol loses a water molecule to give unsaturated aldehyde .

CH3CH(OH)CH2CHO ——-> CH3CH=CHCHO [crotonaldehyde] +H2O


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