On treatment of 100 mL of 0-1 M solution of CoCl 3- 6 H 2 O with excess AgNO 3 - 1-2 - 1022 ions are precipitated- The complex is-A- - Co H 2 O 3 Cl 3- -3 H 2 OB- - Co H 2 O 6- Cl 3C- - Co H 2 O 5 Cl - Cl 2- H 2 OD- - Co H 2 O 4 Cl 2- Cl 2- H 2 O

The correct option is D [Co(H_2O)_4 Cl_2]Cl_2.H_2OMoles of CoCl_3.6H_2O → 100 mL × 0.1 M = 10 × 10^ 3 moles Moles of ions precipitated with excess of AgNO_3= ...

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Byju's Answer

Standard XII

Chemistry

Werner's Coordination Theory

On treatment ...

Question

On treatment of 100 mL of 0.1 M solution of $C o C l_{3} .6 H_{2} O$ with excess $A g N O_{3}; 1.2 \times 10^{22}$ ions are precipitated. The complex is:

[C o (H_{2} O)_{3} C l_{3}] .3 H_{2} O

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[C o (H_{2} O)_{6}] C l_{3}

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[C o (H_{2} O)_{5} C l] C l_{2} . H_{2} O

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[C o (H_{2} O)_{4} C l_{2}] C l_{2} . H_{2} O

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Solution

The correct option is D $[C o (H_{2} O)_{4} C l_{2}] C l_{2} . H_{2} O$
Moles of $C o C l_{3} .6 H_{2} O \to 100 m L \times 0.1 M = 10 \times 10^{- 3} m o l e s$

Moles of ions precipitated with excess of $A g N O_{3} = \frac{1.2 \times 10^{2} 2}{6.02 \times 10^{2} 3} = 0.02 m o l e s$
Number of $C l^{-}$ in ionisation sphere $= \frac{Mole of ion precipitated with excess A g N O_{3}}{Mole of complex}$
= $\frac{0.02}{0.01} = 2$
It means 2 $C l^{-}$ ions present in ionisation sphere
So the answer is $[C o (H_{2} O)_{4} C l_{2}] C l_{2} . H_{2} O$

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Similar questions

Q. On treatment of

100 m L

0.1 M

solution of

C o C l_{3} .6 H_{2} O

with excess

A g N O_{3}; 1.2 \times 10^{22}

ions are precipitated. The complex is :

Q. A six-coordinate complex of formula

C r C l_{6} .6 H_{2}

O is green in colour. A

0.1 M

solution of the complex when treated with excess of

A g N O_{3}

gave

28.7 g

of white precipitate. The formula of the complex would be:

When 0.2 mol $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 0.4 mol of AgCl are obtained. The formula of the complex is

When 1 mole of $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3},$ 3 moles of AgCl are obtained. The formula of the complex is
(a) $[C r C l_{3} (H_{2} O)_{3}] 3 H_{2} O$
(b) $[C r C l_{3} (H_{2} O)_{4}] C l_{2} .2 H_{2} O$
(c) $[C r C l_{3} (H_{2} O)_{5}] C l_{2} . H_{2} O$
(d) $[C r (H_{2} O)_{6}] C l_{3}$

Q. Which isomer of

C r C l_{3} .6 H_{2} O

is dark green in colour and forms one mole of

A g C l

with excess of

A g N O_{3}

solution -

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On treatment of 100 mL of 0.1 M solution of CoCl3.6H2O with excess AgNO3;1.2×1022 ions are precipitated. The complex is:

On treatment of 100 mL of 0.1 M solution of $C o C l_{3} .6 H_{2} O$ with excess $A g N O_{3}; 1.2 \times 10^{22}$ ions are precipitated. The complex is: