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Standard XII

Chemistry

VBT Tetrahedral vs Square Planar

On treatment ...

Question

On treatment of ${[N i {(N H_{3})}_{4}]}_{4}^{2 +}$ with concentrated $H C l$ , two compounds I and II having the same formula, $[N i C l_{2} {(N H_{3})}_{2}]$ are obtained, I can be converted into II by boiling with dilute HCl. A solution of I reacts with oxalic acid to form $[N i (C_{2} O_{4}) {(N H_{3})}_{2}]$ whereas II does not react. Point out the correct statement of the following.

I cis, II trans; both tetrahedral

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I cis, II trans; both square planar

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I trans, II cis; both tetrahedral

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I trans, II cis; both square planar

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Solution

The correct option is B I cis, II trans; both square planar
I is cis and II is trans. And both are square planar.
Oxalic acid is bidentate ligand. Hence, it can replace two cis $C l$ atoms but it cannot replace trans $C l$ atoms.
Also, cis trans isomerism is possible in square planar geometry and not in tetrahedral geometry.

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Similar questions

Q. Which of the following compounds show optical isomerism?
I. cis

- [C o (N H_{3})_{4} C l_{2}]^{+}

II. trans

- [C o (e n)_{2} C l_{2}]^{+}

III. cis

- [C o (e n)_{2} C l_{2}]^{+}

IV.

[C o (e n)_{3}]^{3 +}

Q. First, you name both the compounds. Yes, both of them have the same name. Yet, are they really the same structure, or they are somehow different? Careful inspection should convince you that they are indeed different. Now, how their physical and chemical properties differ? Generally,
i) Cis-isomer has more dipole moment than trans-isomer.
ii) Cis is less stable than trans.
iii) The boiling points of cis isomers are more than those of trans isomers (remember boiling points are directly related to polarity which is determined by dipole moment).
iv) Chemical reactivities of cis and trans also differ from each other.

Arrange the following compounds in the increasing order of their boiling points.

(A)

C H_{3} - C H = C H - C H_{3} (c i s)

(B)

C H_{3} - C H = C H - C H_{3} (t r a n s)

(C)

C H_{3} - C H = C H C l (c i s)

(D)

C H_{3} - C H = C H C l (t r a n s)

Q. (i) Cis-2-butene

\to

trans-2-butene,

Δ H_{1}

(ii) Cis-2-butene

\to

1-butene,

Δ H_{2}

(iii) Trans-2-butene is more stable than cis-2-butene.
(iv) Enthalpy of combustion of 1- butene,

Δ H = - 647.0 k C a l / m o l .

The value of

Δ H_{1}

Δ H_{2}

respectively in K Cal/mole are

Dipole moment will be zero in the complexes

I) $[N i (C N)_{4}]^{2 -}$

II) $C i s - [P t (N H_{3})_{2} C l_{2}]$

III) Trans - $[P t (N H_{3})_{2} C l_{2}]$

Which of the following statements is correct regarding the chirality (optical isomerism) of the cis and trans isomers of the type $M (a a)_{2} b_{2}$ (M stands for a metal, a and b are achiral ligands and aa is a bidentate ligand) ?

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