On vigorous oxidation by permanganate solution $(C H_{3})_{2} C = C H - C H_{2} C H O$ gives :

(C H_{3})_{2} C O

and

O H C - C H_{2} - C H O

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(C H_{3})_{3} C O H

and

H C H O

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(C H_{3})_{2} C O

and

O H C - C H_{2} - C O O H

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(C H_{3})_{2} C O

and

C H_{2} (C O O H)_{2}

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Solution

The correct option is D $(C H_{3})_{2} C O$ and $C H_{2} (C O O H)_{2}$
On vigorous oxidation by permangnate solution $(C H_{3})_{2} C = C H - C H_{2} C H O$ gives $(C H_{3})_{2} C O$ and $C H_{2} (C O O H)_{2}$ . The C=C bond is cleared and oxidised to $- C O O H, - C H O$ group is also oxidised to $- C O O H$ .
$(C H_{3})_{2} C = C H - C H_{2} C H O [O] - ---- \to K M n O_{4} (C H_{3})_{2} C O + C O O H - C H_{2} - C O O H$
Due to vigorous oxidation the $π$ bond breaks and oxidation takes place forming ketone and acid.

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Similar questions

(C H_{3})_{2} C = C H - C H_{2} - C H_{3}

(C H_{3})_{2} C = C H_{2} C H O

Give the nature of A and B in the given reaction. $B K M n O_{4} \leftarrow ---- - H^{+} (C H_{3})_{3} C O H K M n O_{4} / O H^{-} - -------- \to A$

(C H_{3})_{2} C = C H_{2} C H O

O H C - C H O

O H C - C H_{2} - C H_{2} - C H O

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