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Question

One ampere of current is passed for 9650 seconds through molten $$AlCl_3$$. What is the weight in grams of $$Al$$ deposited at cathode? 
(Atomic weight of $$Al = 27$$)


A
0.9
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B
9
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C
0.09
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D
90
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Solution

The correct option is A 0.9
$$i=1  \ A$$, $$t=9650\:s$$
Oxidation number of $$Al$$ in $$AlCl_3=+3$$

$$w=\dfrac{E_{eq}it}{96500}=\dfrac{27\times 1\times 9650}{3\times 96500}$$

$$w=\dfrac{9}{10} = 0.9\: gm$$

Chemistry

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