Question

# One ampere of current is passed for 9650 seconds through molten $$AlCl_3$$. What is the weight in grams of $$Al$$ deposited at cathode? (Atomic weight of $$Al = 27$$)

A
0.9
B
9
C
0.09
D
90

Solution

## The correct option is A 0.9$$i=1 \ A$$, $$t=9650\:s$$Oxidation number of $$Al$$ in $$AlCl_3=+3$$$$w=\dfrac{E_{eq}it}{96500}=\dfrac{27\times 1\times 9650}{3\times 96500}$$$$w=\dfrac{9}{10} = 0.9\: gm$$Chemistry

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