One angle of a cyclic trapezium is double the other. What is the measure of the larger angle ?

60^{\circ}

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80^{\circ}

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75^{\circ}

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120^{\circ}

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Solution

The correct option is D $120^{\circ}$
Let the smaller angle be $x$ , then larger angle is $2 x$ . In a cyclic trapezium sum of two angles is $180^{\circ}$
Hence, $x + 2 x = 180 \Rightarrow x = 60$
Thus larger angle $= 120^{\circ}$

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One angle of a cyclic trapezium is double the other. What is the measure of the larger angle ?

The correct option is D 120∘Let the smaller angle be x, then larger angle is 2x. In a cyclic trapezium sum of two angles is 180∘Hence, x+2x=180⇒x=60Thus larger angle =120∘

The correct option is D $120^{\circ}$
Let the smaller angle be $x$ , then larger angle is $2 x$ . In a cyclic trapezium sum of two angles is $180^{\circ}$
Hence, $x + 2 x = 180 \Rightarrow x = 60$
Thus larger angle $= 120^{\circ}$