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Question

One angles of an isosceles triangle is 120°. What are the other two angles?

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Solution

Given: An isosceles triangle ABC with BAC = 120°.

We know that in an isosceles triangle, two sides are of equal length.

In ΔABC, AB = AC

Also, angles opposite to equal sides of an isosceles triangle are equal.

⇒∠ACB = ABC

Using angle sum property in ΔABC, we have:

ABC + BCA + CAB = 180°

2ABC + 120° = 180°

2ABC = 180° 120°

⇒ ∠ABC = = 30°

Thus, the other two angles of the triangle are of measures 30° each.


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