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Byju's Answer
Standard XII
Mathematics
Parabola
One asymptote...
Question
One asymptote of the hyperbola
2
x
2
+
3
x
y
−
2
y
2
−
7
x
+
y
+
6
=
0
is
x
+
2
y
−
3
=
0
. Then the other asymptote is
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Solution
y
=
3
2
−
x
2
y
=
3
2
−
1
2
(
x
−
1
)
−
1
2
y
=
1
−
1
2
(
x
−
1
)
o
t
h
e
r
a
s
y
m
p
t
o
t
e
y
=
1
+
2
(
x
−
1
)
2
x
−
y
−
1
=
0
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Q.
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