One bag contains 5 black and 3 white balls. Another bag contains 4 black and 5 white balls. One ball is drawn from each bag, the probability that they are of different colour is _____.
Let A be the event of getting black balls
P(A) = 5/8
Let B be the event of getting white balls
P(B) = 3/8
Let C be the event of getting black balls
P(C) = 4/9
Let D be the event of getting white balls
P(D) = 5/9
Now, Let E be the event that ball drawn from each bag will be different
P(E) = P(A) P(D) + P(B) P(C)
= (5/8) (5/9) + (3/8) (4/9)
= 37/72