One body is dropped, while a second body is thrown downward with an initial velocity of 1m s−1 simultaneously. The separation between these is 18m after a time
A
4.5s
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B
4.5s
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C
18s
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D
36s
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Solution
The correct option is C18s Let t be the time after which the separation between two bodies is 18m Let Srel be the relative distance between two bodies after time t ⇒Srel=18m Relative acceleration of two bodies during downfall =arel=g−g=0 Relative initial velocity of two bodies =urel=1−0=1m/s Srel=urelt+12arelt2 ⇒18=1×t+0 ⇒t=18s