One cationic complex has two isomers, $A$ and $B$ . Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ and one $S O_{4}^{2 -}$ stoichiometrically. $A$ gives white precipitate with $B a C l_{2}$ while $B$ give yellow precipitate with $A g N O_{3}$ . This means $A$ and $B$ are ionization isomers.
If true enter 1, else enter 0.

Open in App

Solution

Given that one cationic complex has two isomers, $A$ and $B$ . Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ and one $S O_{4}^{2 -}$ stoichiometrically. $A$ gives white precipitate with $B a C l_{2}$ while $B$ give yellow precipitate with $A g N O_{3}$ .
$A$ is $[C o (N H_{3})_{5} B r] S O_{4}$ : It gives white precipitate with $B a C l_{2}$ due to the reaction of $S O_{4}^{2 -}$ with $B a C l_{2}$ giving $B a S O_{4}$ .
$B$ is $[C o (N H_{3})_{5} S O_{4}] B r$ : It gives yellow precipitate with $A g N O_{3}$ due to the reaction of $B r^{-}$ with $A g N O_{3}$ giving $A g B r$ .
$A$ and $B$ are therefore, ionization isomers.
Hence, the correct answer is 1.

Suggest Corrections

Similar questions

One cationic complex has two isomers A and B. Each has one

C o^{3 +}

, five

N H_{3}

, one

B r^{-}

, and one

S O_{4}^{2 -}

stoichiometrically. A gives white ppt with

B a C l_{2}

while B give yellow ppt with

A g N O_{3}

B can be :

One cationic complex has two isomers A and B. Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ , and one $S O_{4}^{2 -}$ stoi-chiometrically. A gives white ppt with $B a C l_{2}$ whle B give yellow ppt with $A g N O_{3}$ .
B can be:

Join BYJU'S Learning Program

One cationic complex has two isomers, A and B. Each has one Co3+, five NH3, one Br− and one SO2−4 stoichiometrically. A gives white precipitate with BaCl2 while B give yellow precipitate with AgNO3. This means A and B are ionization isomers. If true enter 1, else enter 0.