One cationic complex has two isomers A and B- Each has one Co3- five NH3- one Br- and one SO2-4 stoichiometrically- A gives white ppt with BaCl2 while B give yellow ppt with AgNO3-B can be -

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Standard XII

Chemistry

Hydrate Isomerism

One cationic ...

Question

One cationic complex has two isomers A and B. Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ , and one $S O_{4}^{2 -}$ stoichiometrically. A gives white ppt with $B a C l_{2}$ while B give yellow ppt with $A g N O_{3}$ .

B can be :

[C o (N H_{3})_{5} S O_{4}] B r

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[C o (N H_{3})_{5}] B r S O_{4}

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[C o (N H_{3})_{3} B r (S O_{4})] .2 N H_{3}

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None of these

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Solution

The correct option is A $[C o (N H_{3})_{5} S O_{4}] B r$
B gives yellow ppt. with $A g N O_{3}$ confirming the formation of $A g B r$ . Hence it is confirmed that $B r$ is out of the coordination sphere. B is $[C o (N H_{3})_{5} S O_{4}] B r$

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Similar questions

One cationic complex has two isomers A and B. Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ , and one $S O_{4}^{2 -}$ stoi-chiometrically. A gives white ppt with $B a C l_{2}$ whle B give yellow ppt with $A g N O_{3}$ .
B can be:

Q. One cationic complex has two isomers,

A

and

B

. Each has one

C o^{3 +}

, five

N H_{3}

, one

B r^{-}

and one

S O_{4}^{2 -}

stoichiometrically.

A

gives white precipitate with

B a C l_{2}

while

B

give yellow precipitate with

A g N O_{3}

. This means

A

and

B

are ionization isomers.
If true enter 1, else enter 0.

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One cationic complex has two isomers A and B. Each has one Co3+, five NH3, one Br−, and one SO2−4 stoichiometrically. A gives white ppt with BaCl2 while B give yellow ppt with AgNO3.B can be :

The correct option is A [Co(NH3)5SO4]BrB gives yellow ppt. with AgNO3 confirming the formation of AgBr. Hence it is confirmed that Br is out of the coordination sphere. B is [Co(NH3)5SO4]Br

One cationic complex has two isomers A and B. Each has one $C o^{3 +}$ , five $N H_{3}$ , one $B r^{-}$ , and one $S O_{4}^{2 -}$ stoichiometrically. A gives white ppt with $B a C l_{2}$ while B give yellow ppt with $A g N O_{3}$ .

B can be :

The correct option is A $[C o (N H_{3})_{5} S O_{4}] B r$
B gives yellow ppt. with $A g N O_{3}$ confirming the formation of $A g B r$ . Hence it is confirmed that $B r$ is out of the coordination sphere. B is $[C o (N H_{3})_{5} S O_{4}] B r$