CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Vernier Caliper

One centimetr...

Question

One centimetre on the main scale of vernier callipers is divided into ten equal parts . If 20 division of vernier scale coincide with 19 small division of the main scale then what will be the least count of the callipers

Open in App

Solution

Least count= 1/n(MSD)

Suggest Corrections

thumbs-up

0

Similar questions

Q. In a vernier callipers, 20 divisions on the vernier scale coincides with 17 divisions on the main scale. If one cm on the main scale is divided into 20 equal parts, then find the least count of the callipers.

Q. In a Vernier callipers, 1 cm of the main scale is divided into 20 equal parts. 19 divisions of the main scale coincide with 20 divisions on the vernier scale. Find the least count of the instrument.

Q. 19 divisions on the main scale of a vernier callipers coincide with 20 divisions on the vernier scale. If each division on the main scale is of 1 cm, determine the least count of instrument.

Q. A vernier callipers has its main scale of

10 c m

equally divided into

200

equal parts. Its vernier scale of

25

divisions coincides with

12 m m

on the main scale. The least count of the instrument is -

One 8cm on the main scale of the vernier callipers is divided into 10 equal parts. If the 10 divisions of the vernier concide with the small divisions the main scale, the least 10 divisions of the callipers is :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Vernier Caliper and Screw Gauge

PHYSICS

Watch in App

explore_more_icon

Explore more

Vernier Caliper

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon