One commercial system removes SO2 emission from smoke at 95∘C by the following set of reaction:
SO2(g)+Cl2(g)→SO2Cl2(g)
SO2Cl2(g)+H2O(l)→H2SO4+HCl
H2SO4+Ca(OH)2→CaSO4+H2O
Grams of CaSO4 that may be produced from 3.78g of SO2 are :
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Solution
The reactions are as follows:
SO2(g)+Cl2(g)→SO2Cl2(g)
SO2Cl2(g)+H2O(l)→H2SO4+HCl
H2SO4+Ca(OH)2→CaSO4+H2O From reactions, we can see that one mole of SO2 produces one mole of CaSO4. Moles of SO2 (given) =3.7864=0.0590 mol. So, mass of CaSO4 produced =0.0590×136=8 g.