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Question

One commercial system removes SO2 emission from smoke at 95C by the following set of reaction:

SO2(g)+Cl2(g)SO2Cl2(g)

SO2Cl2(g)+H2O(l)H2SO4+HCl

H2SO4+Ca(OH)2CaSO4+H2O

Grams of CaSO4 that may be produced from 3.78g of SO2 are :

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Solution

The reactions are as follows:

SO2(g)+Cl2(g)SO2Cl2(g)

SO2Cl2(g)+H2O(l)H2SO4+HCl

H2SO4+Ca(OH)2CaSO4+H2O
From reactions, we can see that one mole of SO2 produces one mole of CaSO4.
Moles of SO2 (given) =3.7864=0.0590 mol.
So, mass of CaSO4 produced =0.0590×136=8 g.

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